(x^2-3)^2+4(x^2-3)+4=0

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Solution for (x^2-3)^2+4(x^2-3)+4=0 equation: 



(x^2-3)^2+4(x^2-3)+4=0

We multiply parentheses

4x^2+(x^2-3)^2-12+4=0

We add all the numbers together, and all the variables

4x^2+(x^2-3)^2-8=0

We move all terms containing x to the left, all other terms to the right

4x^2+(x^2-3)^2=8

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